I whant to simulate BER for BPSK but for 5 or 6 user not for 1 user what is the changement applicated in this programme. some 0s my get interpreted as 1s and vice versa (0 and 1 are basic elements ie bits in a digital transmission). Reply Krishna Sankar July 26, 2012 at 5:27 am @candy: well, when we flip a coin we have a 50% chance of getting the call correct. Unsourced material may be challenged and removed. (March 2013) (Learn how and when to remove this template message) In digital transmission, the number of bit errors is the number of received http://performancepccanada.com/bit-error/bit-error-rate-and-data-rate-relation.php
I try the matlab function using demodh= modem.pskdemod(ht, ‘outputType', ‘bit','DecisionType', ‘LLR', ‘NoiseVariance', sigma); dec_inputt=demodulate(demodh,rt); but the bit that I'm receive sort like it have inverse sign. With Binary Phase Shift Keying (BPSK), the binary digits 1 and 0 maybe represented by the analog levels and respectively. Reply Krishna Sankar April 27, 2010 at 5:22 am @STIVE CHLEF: Well, if you have 5/6 users, how are you planning to distinguish them at the receiver? I'm very new at digital communication, so I'm sorry for these bad questions Reply Krishna Sankar December 26, 2012 at 7:06 am @Ozgee: Replies: 1/ This simulation is doing bit error
This is because each type of modulation performs differently in the presence of noise. It is about the square root raised cosine pulse ,we need to plot it with different roll-off factor(B=0.25,B=0.5,B=1. Create a free website or blog at WordPress.com. %d bloggers like this: ERROR The requested URL could not be retrieved The following error was encountered while trying to retrieve the URL: Patterns are: all ones, 1:7, 2 in 8, 3 in 24, and QRSS.
Can u suggest me a Block for finding Pe or a Program to call from .m file..? I determine two waveforms, Tb and BW, then I'm trying to draw the plot of Pe versus BW. Returning to BER, we have the likelihood of a bit misinterpretation p e = p ( 0 | 1 ) p 1 + p ( 1 | 0 ) p 0 Bit Error Rate Tester where is my mistake ?
Reply Krishna Sankar November 15, 2010 at 2:14 am @Ahmed: For 8 PSK case, you may use the article on 16PSK as a reference [symbol error rate] http://www.dsplog.com/2008/03/18/symbol-error-rate-for-16psk/ [bit error rate] Acceptable Bit Error Rate Additive noise n is real AWGN process (same as in (1)). I don't know how can I select the average SNR in (7), (8),(15) ,… and the second problem is ,if we select the SNR whit gama distribution in matlab for example: I also noticed that this scaling change for system to system e.g for non coherent 4FSK -it becomes like (10^(-sqrt(2)*Es_2N0_dB(ii)/20))*n becoz in 4FSK i need variance 0.5.so i scaled it to
but i need it's paper too. Bit Error Rate Calculator of sub carrier then how the BER of indivisual subcarriers are related??? Reply Krishna Sankar March 30, 2010 at 4:33 am @rekha: The BER performance of OFDM in AWGN is comparable to the no OFDM case. For that first I am trying to get probability of error rate vs snr of different modulation techniques.
Please try the request again. However, just make sure that scaling is correct. Bit Error Rate Vs Snr what and where would u start from? Bit Error Rate Measurement The first problem is finding average SNR in mode(n).
p.508. weblink It is necessary to balance all the available factors to achieve a satisfactory bit error rate. Reply Krishna Sankar December 7, 2009 at 4:38 am @Obinna O: Hope you have finished the project by now. I need ur guidelines to work in communication field or in signal processing so that I can prepare for my future… Pls do reply waiting for ur precious reply.. Bit Error Rate Pdf
Eb_No_dB =[0:10], -> 0 to 10dB in steps of 1dB Eb_No_dB =[0:20], -> 0 to 20dB in steps of 1dB Eb_No_dB =[0:30], -> 0 to 30dB in steps of 1dB Reply What is the minimum Es/NodB to guarantee a P(e) < 10^-5? I will try to answer to the best of my knowledge. navigate here NNAMDI Reply Krishna Sankar November 12, 2009 at 5:33 am @Egerue: You are right.
Krishna Would you help me in my project!!! BER comparison between BPSK and differentially encoded BPSK with gray-coding operating in white noise. can you help me in this….. Bit Error Rate Testing The two are strongly coupled.
As one of the main parameters of interest in any data link is the number of errors that occur, the bit error rate is a key parameter. n=1/sqrt(2)*[randn(1,N) + j*randn(1,N)] Reply Krishna Sankar July 5, 2012 at 5:12 am @Zoe: 1. Register for our newsletter More tutorials RF mixersCombiners splittersAttenuatorsDirectional couplerFiltersButterworthChebychevBesselDoherty amplifierEnvelope tracking Latest news TV White Space technology ready for real-world commercial applicationsNokia expands LTE portfolio with Cloud Packet Core solutionToshiba his comment is here As a result, it is necessary to assess the performance of the system, and bit error rate, BER, provides an ideal way in which this can be achieved.
Reply Thiyagi January 22, 2012 at 6:44 pm Yes Mr.Krishna… I'm currently pursuing my M.Tech(Communication Engineering) in VIT.. Pls, you are indeed a very good teacher, help me out Thanks, you are really very helpful, you must really reap the fruit of your efforts. You can check couple of points: a) awgn : whether the noise power is as expected. Idea is to find the area under the tail of the Gaussian curve.
you can check by command max((10^(-Eb_N0_dB(ii)/20)*n))= 1.01 where as max((10^(-Eb_N0_dB(ii)/10)*n))= 0.3251 so its clear scaling…..remember before these commands i just removed the complex part i.e n = 1/sqrt(2)*[randn(1,N)]; for my easyness. Reply Krishna Sankar April 13, 2010 at 6:18 am @fizzle: Well, if you divide signal power by noise power, the resultant is signal to noise ratio Reply vj1892 March 29, Thanks Reply Egerue Nnamdi November 2, 2009 at 10:26 pm Hi krishna, I have actually read the answers given to you by the concerns generated by the formula below 10^(-Eb_N0_dB(ii)/20)*n for Thanks a lot, i will be very grate ful to get help from you guys.
these are real points then why to add complex noise …we can directly add real noise of unit variance as follows… N = 10^6 % number of bits or symbols rand(‘state',100); Bridgetap - Bridge taps within a span can be detected by employing a number of test patterns with a variety of ones and zeros densities. If errors are introduced into the data, then the integrity of the system may be compromised. for ii = 1:length(Eb_N0_dB) what is the concept of this function?
NNAMDI Reply Egerue Nnamdi November 8, 2009 at 8:00 pm Hi Krishna. Here an AWGN channel is assumed. Comment. 2.The noise variance is sigma^2 =N0/2 hence for each value of Es/NodB you can derive the associated sigma^2 that you need to generate your additive white gaussian noise. 3.Generate a Reduce bandwidth: Another approach that can be adopted to reduce the bit error rate is to reduce the bandwidth.
Reply ruby January 27, 2013 at 4:10 am pls can you help solve this question; Given a stationary transmitter is sending at a center frequency of 900 MHz, the Please give me more direction, by giving me an example of what you mean by changing the VALUE of Eb_No_dB. I am keeping the signal swing the same and reducing the swing of noise voltage to simulate various Eb/N0 values. Here is my code: clear b = 10000; % number of bits or symbols %----------- Transmitter--------- %Message signal ip = rand(1,b)>0.5; % generating 0,1 with equal probability %generating m-sequence polynomial=[6 1
Reply Krishna Sankar December 7, 2009 at 5:33 am @fatima: I believe it should be reasonably straightforward to modify the gaussian channel used in this post to a binary symmetric channel. reply Can you little bit tell me how to simulate the Uncoded BER and ergodic capacity for webb channel using QPPM modulation.